Basically the Question generally is to Write a C function to print all numbers from 1 to m (m is the input no) without any loop specifically for, while, switch, do and recursion
#include
#include
char globalStr[1000000];
void nprint(int n)
{
char strn[7], *cp;
sprintf(strn,"%d\n", n);
cp = strstr(globalStr, strn);
*(cp + strlen(strn)) = 0;
printf("%s",globalStr);
}
int main(){
int n,i;
globalStr[0] = 0;
/* Lopp is not allowed only in the function nprint()......still if not convinced, you are free to form the string manually :P*/
for(i = 1;i<32768;i++)
sprintf(globalStr,"%s%d\n", globalStr,i);
scanf("%d",&n);
nprint(n);
return 0;
}
For CPP, there is a better method,
#include
class a{
public:
a(){std::cout<<++i<
private:
static int i;
};
int a::i;
int main(){
int n=0;
std::cout<<"Enter the maximum number that you want to print: ";
std::cin>>n;
a* array=new a[n];
//system("pause");
return 0;
}
Saturday, April 10, 2010
print 1-100 no.swithout loop in c
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