#include
#define NO
#define YES
int main()
{
int i = 5,j;
if (i>5) j=YES;
else j=NO;
printf("%d",j);
}
Output: Expression syntax in function main
Explanation: Because when assigning j with YES or NO we don't know what is the value of YES or NO.
Thursday, December 3, 2009
Using define without assigning value
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